Q.1: What is the coefficient of x in y – 8 + x ?
a) 8
b) 1
c) (-8)
Q.2: The sum of pq + 3p and 4q – 3pq is ________________.
a) 3p + 4q – 2pq
b) 3p + 4pq – 4q
c) 7pq – 2pq
Q.3: The constant term in the expression 1 + x + xy is ________.
a) x
b) xy
c) 1
Q.4: The number of terms in the expression 0.5r + 0.6pr – 2.5qr is ________________.
a) 3
b) 2
c) 4
Q.5: The expression 47z + 38y is ____________.
a) monomial
b) binomial
c) trinomial
Q.6: By subtracting 2t + 15pq from 18pq – 5t, we will get _______________.
a) 3pq – 3t
b) 3pq – 7t
c) 3pq + 7t
Q.7: If x = 0 and y = (-1), then the value of 5x + 2y will be ________.
a) 0
b) (-1)
c) (-2)
Q.8: The value of expression 2( x – 4 ) + 10 at x =2 is ___________.
a) 6
b) (-6)
c) (-3)
Q.9: What should be the value of y if y2 + y – b = 3 for y = 1 ?
a) 0
b) 1
c) (-1)
Q.10: The common factor in the terms 35xy and (-14)r is ___________.
a) 7
b) 10
c) 7xyr
Q.11: Area of the rectangle with length as 3q and breadth as 4p is _______.
a) 12pq
b) 7pq
c) 14pq
Q.12: Value of (9x + 6) and (4y + 3) is _________________.
a) 36xy + 27x + 24y + 18
b) 18xy + 42xy + 20
c) 12xy + 14x + 21y + 2
Q.13: The suitable identity to find the value of (4 + p) (4 + p) is ______________.
a) (a – b)2
b) (a + b)2
c) Either ‘a’ or ‘b’
Q.14: Using identity (x + a) (x + b) = x2 + (a + b)x + ab, find the answer of (n + 5) (n + 6).
a) n2 + 30n + 30
b) n2 + 12n + 20
c) n2 + 11n + 30
Q.15: (a – b)2 = ______________.
a) a2 – 2ab – b2
b) a2 + 2ab – b2
c) a2 – 2ab + b2
Q.16: Find the value of 95 and 105 by using suitable identity.
a) 9925
b) 9975
c) 9950
Q.17: The product of 2x and (5xy + 3y) is _______________.
a) 16x2 y
b) 10x2 y + 6xy
c) 6xy + 15x2
Q.18: Using suitable identity, find the value of (7.3)2
a) 53.29
b) 53.29
c) 5.329
Q.19: Using the identity (x + a) (x + b) = x2 + (a + b)x + ab, find the value of 101 x 102.
a) 10002
b) 10302
c) 10332
Q.20: The length, breadth and height of a cuboid is 2a3 , 5ab and 3x respectively. Find its volume.
a) 30a4 bx
b) 30a3 bx
c) 15abx
- b
- a
- c
- a
- b
- b
- c
- a
- c
- a
- a
- a
- b
- c
- c
- b
- b
- a
- b
- a
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